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CooldudeRama17

_n][

] 1/n[(1+n)(2+n)..............(n+n)]^1/n

Let the limit be =I

I= [(1/n+1)(2/n+1)........................(n/n +1)]^1/n

take log of both sides

now

log I=1/n ( _{[r=1 ]}^{[r=infinity ]} log(r/n+1))

now this is limit of sum

logI= _{[ 0]}

^{[ 1]} log(x+1).dx

log I=log(4/e)

answer is 4/e

is my answer correct

dont i look like an idiot