hey u all ppl i have got the shortest method!!!
one which shakir wanted!!
we take triangle ABC and we take angles in it .
angle A=pi/4 we take
B=2
C=2
we now construct the angle bisectors of all sides and let then intersect at O
side BC =5(cot
+cot
)=10sin(
+
)/( sin(
+
)+cos(
-
) )
which is minimum if
cos(
-
)=1
also bcox angle A=pi/4
+
=3pi/8
using this we will get the answer which we wanted that is
10sqroot(2+sqroot(2))/(2+sqrroot(2+sqroot(2)))
Isnt it a very good method!!!!!!
Plaese rate me bcoz i have really produced an excellent solution!!
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