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2 Apr 2007 12:28:38 IST
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m putting this question on behalf of "Karthik-abhiram"... pls solve this for him ----------------------------------------------------------------------------------------------------------- The position vectors a,b,c and d {all in vectors} of four points A,B,C and D on a plane are such that (a-d).(b-c)=(b-d).(c-a)=0, {all in vectors} then the pont D is 1]centroid of  ABC 2] ortho centre of ABC 3]circumcentre of ABC 4]None of these. plzz help ,and post a detailed solution plz and i want theoritical proof plzz as it would increase our mind to think better for other problems like these
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2 Apr 2007 12:39:58 IST
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THe answer seems 2 b
3]circumcentre of ABC.
Is it right?
If yes, I'll give the detailed solution.
DO RATE & REPLY....
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2 Apr 2007 12:41:13 IST
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i m sorry its not that.........thanx for trying........
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IF U THINK U CAN, U CAN........IF U THINK U CAN'T, U CAN'T.........
BE THE BEST OF WHAT EVER YOU ARE!!!
THEN U WILL SUCCEED FOR SURE!!!
     
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2 Apr 2007 12:56:15 IST
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Hey the answer is orthocentre option (2) check that first of all, in all options u hav triangle ABC..... so, keep it as fixed.... now, try for the positions of D... the given equations imply that AD.BC=0 and BD.AC=0 (. means doy product) so, AD and BC are perpendicular and so are BD and AC..... for a given triangle ABC, this is possible only with the orthocentre..... hope m clear... thank u... Goutham Harsha
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2 Apr 2007 13:02:08 IST
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hey kartik i already told u its : b
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light travels the fastest ??? NO
wherever light goes it always finds that darkness has already got there |
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yea yea i just want the idea to solve these type of problems...........
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IF U THINK U CAN, U CAN........IF U THINK U CAN'T, U CAN'T.........
BE THE BEST OF WHAT EVER YOU ARE!!!
THEN U WILL SUCCEED FOR SURE!!!
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5 Apr 2007 17:52:20 IST
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Hello karthik_abiram Most of the problems in the vector algebra are ended with only three major things 1. A line vector A (a) and B (b) are two vectors then their line vector AB is b-a 2. Dot product of two vectors a.b = |a||b| cos t Special cases of the dot product
Since i and j and k are all one unit in length and they are all mutually perpendicular, we have
i.i = j.j = k.k = 1
and i.j = j.i = i.k = k.i = j.k = k.j = 0. As cos 0 =1 3. Cross Product If we let the angle between A and B be  , then the cross product of A and B can be expressed as A x B = A B sin() Same way sin90=1 so you can calculate the different unit vaectors.
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5 Apr 2007 18:53:05 IST
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Thank you sir and special thanks to my didi , for this and also for answering all the vectors.....
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IF U THINK U CAN, U CAN........IF U THINK U CAN'T, U CAN'T.........
BE THE BEST OF WHAT EVER YOU ARE!!!
THEN U WILL SUCCEED FOR SURE!!!
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