the LHS is a sine function, hence, the range of LHS = [-1,1]
for a solution, the graph of RHS should intersect the graph of sine function of the LHS,
which is possible only if
for some real 'x', -1=< RHS <= 1
now for x>0 , RHS > 0
also for x = -sqrt(3), LHS=0 and RHS = 1.9
x = - 3 sqrt(3) /2 , LHS=1 and RHS = -8.5 (approx)
i.e. the polynomial in the RHS changes its sign for some x in the range, ( - 3 sqrt(3) /2 , sqrt(3) ) ...
Thus there exist only one solution to the equation